5c/8+7c/12=(15/48)+c

Solution for 5c/8+7c/12=(15/48)+c equation:

5c/8+7c/12=(15/48)+c

We move all terms to the left:

5c/8+7c/12-((15/48)+c)=0


Domain of the equation: 48)+c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

5c/8+7c/12-((+15/48)+c)=0

We calculate fractions


11520c^2/18432c+10752c^2/18432c+()/18432c=0

We multiply all the terms by the denominator


11520c^2+10752c^2+()=0

We add all the numbers together, and all the variables

22272c^2=0

a = 22272; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·22272·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{44544}=0$