5cos(2t/pi)

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Solution for 5cos(2t/pi) equation: 


t in (-oo:+oo)

5*cos((2*t)/pi) = 0

cos((2*t)/pi) = 0

cos((2*t)/pi) = 0  <=>  (2*t)/pi = pi*k_1+pi/2 i k_1 należy do I

t_1 = pi*k_1+pi/2

(2*t)/pi-t_1 = 0

(2/pi)*t-t_1 = 0 // + t_1

(2/pi)*t = t_1 // : 2/pi

t = t_1/(2/pi)

t = pi*k_1+pi/2/(2/pi) i k_1 należy do I

5*cos((2*t)/pi) = 0  <=>  5 = 0 or 5*cos((2*t)/pi) = 0  <=>  cos((2*t)/pi) = 0

t = pi*k_1+pi/2/(2/pi)

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