5cos(2x)+7=cos(2x)+8

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Solution for 5cos(2x)+7=cos(2x)+8 equation:


Simplifying
5cos(2x) + 7 = cos(2x) + 8

Remove parenthesis around (2x)
5cos * 2x + 7 = cos(2x) + 8

Reorder the terms for easier multiplication:
5 * 2cos * x + 7 = cos(2x) + 8

Multiply 5 * 2
10cos * x + 7 = cos(2x) + 8

Multiply cos * x
10cosx + 7 = cos(2x) + 8

Reorder the terms:
7 + 10cosx = cos(2x) + 8

Remove parenthesis around (2x)
7 + 10cosx = cos * 2x + 8

Reorder the terms for easier multiplication:
7 + 10cosx = 2cos * x + 8

Multiply cos * x
7 + 10cosx = 2cosx + 8

Reorder the terms:
7 + 10cosx = 8 + 2cosx

Solving
7 + 10cosx = 8 + 2cosx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2cosx' to each side of the equation.
7 + 10cosx + -2cosx = 8 + 2cosx + -2cosx

Combine like terms: 10cosx + -2cosx = 8cosx
7 + 8cosx = 8 + 2cosx + -2cosx

Combine like terms: 2cosx + -2cosx = 0
7 + 8cosx = 8 + 0
7 + 8cosx = 8

Add '-7' to each side of the equation.
7 + -7 + 8cosx = 8 + -7

Combine like terms: 7 + -7 = 0
0 + 8cosx = 8 + -7
8cosx = 8 + -7

Combine like terms: 8 + -7 = 1
8cosx = 1

Divide each side by '8osx'.
c = 0.125o-1s-1x-1

Simplifying
c = 0.125o-1s-1x-1

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