5cos(2x)-3sin(2x)=4

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Solution for 5cos(2x)-3sin(2x)=4 equation:


Simplifying
5cos(2x) + -3sin(2x) = 4

Remove parenthesis around (2x)
5cos * 2x + -3sin(2x) = 4

Reorder the terms for easier multiplication:
5 * 2cos * x + -3sin(2x) = 4

Multiply 5 * 2
10cos * x + -3sin(2x) = 4

Multiply cos * x
10cosx + -3sin(2x) = 4

Remove parenthesis around (2x)
10cosx + -3ins * 2x = 4

Reorder the terms for easier multiplication:
10cosx + -3 * 2ins * x = 4

Multiply -3 * 2
10cosx + -6ins * x = 4

Multiply ins * x
10cosx + -6insx = 4

Solving
10cosx + -6insx = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '6insx' to each side of the equation.
10cosx + -6insx + 6insx = 4 + 6insx

Combine like terms: -6insx + 6insx = 0
10cosx + 0 = 4 + 6insx
10cosx = 4 + 6insx

Divide each side by '10osx'.
c = 0.4o-1s-1x-1 + 0.6ino-1

Simplifying
c = 0.4o-1s-1x-1 + 0.6ino-1

Reorder the terms:
c = 0.6ino-1 + 0.4o-1s-1x-1

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