5cos(2y)-4sin(2y)=0

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Solution for 5cos(2y)-4sin(2y)=0 equation:


Simplifying
5cos(2y) + -4sin(2y) = 0

Remove parenthesis around (2y)
5cos * 2y + -4sin(2y) = 0

Reorder the terms for easier multiplication:
5 * 2cos * y + -4sin(2y) = 0

Multiply 5 * 2
10cos * y + -4sin(2y) = 0

Multiply cos * y
10cosy + -4sin(2y) = 0

Remove parenthesis around (2y)
10cosy + -4ins * 2y = 0

Reorder the terms for easier multiplication:
10cosy + -4 * 2ins * y = 0

Multiply -4 * 2
10cosy + -8ins * y = 0

Multiply ins * y
10cosy + -8insy = 0

Solving
10cosy + -8insy = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '8insy' to each side of the equation.
10cosy + -8insy + 8insy = 0 + 8insy

Combine like terms: -8insy + 8insy = 0
10cosy + 0 = 0 + 8insy
10cosy = 0 + 8insy
Remove the zero:
10cosy = 8insy

Divide each side by '10osy'.
c = 0.8ino-1

Simplifying
c = 0.8ino-1

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