5d+2(2-6)=3(1+d)+1

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Solution for 5d+2(2-6)=3(1+d)+1 equation: 



5d+2(2-6)=3(1+d)+1

We move all terms to the left:

5d+2(2-6)-(3(1+d)+1)=0

We add all the numbers together, and all the variables

5d-(3(d+1)+1)+2(-4)=0

We add all the numbers together, and all the variables

5d-(3(d+1)+1)-8=0



We calculate terms in parentheses: -(3(d+1)+1), so:

3(d+1)+1

We multiply parentheses

3d+3+1

We add all the numbers together, and all the variables

3d+4

Back to the equation:

-(3d+4)



We get rid of parentheses

5d-3d-4-8=0

We add all the numbers together, and all the variables

2d-12=0

We move all terms containing d to the left, all other terms to the right

2d=12

d=12/2

d=6

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