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5d+2(2-d)=3(1+d)
We move all terms to the left:
5d+2(2-d)-(3(1+d))=0
We add all the numbers together, and all the variables
5d+2(-1d+2)-(3(d+1))=0
We multiply parentheses
5d-2d-(3(d+1))+4=0
We calculate terms in parentheses: -(3(d+1)), so:We add all the numbers together, and all the variables
3(d+1)
We multiply parentheses
3d+3
Back to the equation:
-(3d+3)
3d-(3d+3)+4=0
We get rid of parentheses
3d-3d-3+4=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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