5d+2(2d)=3(1+d)-+1

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Solution for 5d+2(2d)=3(1+d)-+1 equation:



5d+2(2d)=3(1+d)-+1
We move all terms to the left:
5d+2(2d)-(3(1+d)-+1)=0
We add all the numbers together, and all the variables
5d+22d-(3(d+1)-+1)=0
We add all the numbers together, and all the variables
27d-(3(d+1)-+1)=0
We use the square of the difference formula
27d-(3(d+1)-1)=0
We calculate terms in parentheses: -(3(d+1)-1), so:
3(d+1)-1
We multiply parentheses
3d+3-1
We add all the numbers together, and all the variables
3d+2
Back to the equation:
-(3d+2)
We get rid of parentheses
27d-3d-2=0
We add all the numbers together, and all the variables
24d-2=0
We move all terms containing d to the left, all other terms to the right
24d=2
d=2/24
d=1/12

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