5d+2(2d)=3(1+d)-+1

Solution for 5d+2(2d)=3(1+d)-+1 equation:

5d+2(2d)=3(1+d)-+1

We move all terms to the left:

5d+2(2d)-(3(1+d)-+1)=0

We add all the numbers together, and all the variables

5d+22d-(3(d+1)-+1)=0

We add all the numbers together, and all the variables

27d-(3(d+1)-+1)=0

We use the square of the difference formula

27d-(3(d+1)-1)=0


We calculate terms in parentheses: -(3(d+1)-1), so:

3(d+1)-1

We multiply parentheses

3d+3-1

We add all the numbers together, and all the variables

3d+2

Back to the equation:

-(3d+2)


We get rid of parentheses

27d-3d-2=0

We add all the numbers together, and all the variables

24d-2=0

We move all terms containing d to the left, all other terms to the right

24d=2

d=2/24

d=1/12