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5d+d=5d^2
We move all terms to the left:
5d+d-(5d^2)=0
determiningTheFunctionDomain -5d^2+5d+d=0
We add all the numbers together, and all the variables
-5d^2+6d=0
a = -5; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-5)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-5}=\frac{-12}{-10} =1+1/5 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-5}=\frac{0}{-10} =0 $
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