If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5e^2-5e-30=0
a = 5; b = -5; c = -30;
Δ = b2-4ac
Δ = -52-4·5·(-30)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-25}{2*5}=\frac{-20}{10} =-2 $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+25}{2*5}=\frac{30}{10} =3 $
| 6.9g+5=1.9g+15 | | 4+2p=10(35p-2) | | x+7+3x-18+x-9+x+21+x+17=180 | | 6f2+6f+70=-2 | | (5^3)^-4y=5 | | 2x+((12-4x)/2)=6 | | 1.5^n=1.1 | | S=2/3y+4 | | |x-3|+8=25 | | 4(7+1/2x)=16x-14 | | 5-4a=5a-4 | | 7x^2-16x-1=0 | | 8x-(2x-3)=2(x+3,5) | | 5x-(8x+6)=12 | | 12=13+5n+-5n | | 2x−5+3x−8+10x−17=180 | | 2x+3=4x-6+× | | -x^2+11x-13=0 | | C=650y+300y | | (7r+5)(2r−6)=0 | | 3.98=x-11.24 | | 4x^2+8x-14=0 | | 41=4x−7 | | 5*x+8=-2*x+5 | | -6=x-2-10 | | 17-11=h-1 | | 2x+20+3x+15+135=180 | | 8z-9=-1 | | 5x–12=2x+12 | | 110-24x=20-4 | | 5x+7x+120=180 | | 135°n=180°n-360° |