5h(22-2h)=-5

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Solution for 5h(22-2h)=-5 equation:



5h(22-2h)=-5
We move all terms to the left:
5h(22-2h)-(-5)=0
We add all the numbers together, and all the variables
5h(-2h+22)-(-5)=0
We add all the numbers together, and all the variables
5h(-2h+22)+5=0
We multiply parentheses
-10h^2+110h+5=0
a = -10; b = 110; c = +5;
Δ = b2-4ac
Δ = 1102-4·(-10)·5
Δ = 12300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{12300}=\sqrt{100*123}=\sqrt{100}*\sqrt{123}=10\sqrt{123}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-10\sqrt{123}}{2*-10}=\frac{-110-10\sqrt{123}}{-20} $
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+10\sqrt{123}}{2*-10}=\frac{-110+10\sqrt{123}}{-20} $

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