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5h(h+4)=0
We multiply parentheses
5h^2+20h=0
a = 5; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·5·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*5}=\frac{-40}{10} =-4 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*5}=\frac{0}{10} =0 $
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