5h+2h(11-h)=2

Solution for 5h+2h(11-h)=2 equation:

5h+2h(11-h)=2

We move all terms to the left:

5h+2h(11-h)-(2)=0

We add all the numbers together, and all the variables

5h+2h(-1h+11)-2=0

We multiply parentheses

-2h^2+5h+22h-2=0

We add all the numbers together, and all the variables

-2h^2+27h-2=0

a = -2; b = 27; c = -2;
Δ = b2-4ac
Δ = 272-4·(-2)·(-2)
Δ = 713
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{713}}{2*-2}=\frac{-27-\sqrt{713}}{-4}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{713}}{2*-2}=\frac{-27+\sqrt{713}}{-4}
$