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5h-15/h=5
We move all terms to the left:
5h-15/h-(5)=0
Domain of the equation: h!=0We multiply all the terms by the denominator
h∈R
5h*h-5*h-15=0
We add all the numbers together, and all the variables
-5h+5h*h-15=0
Wy multiply elements
5h^2-5h-15=0
a = 5; b = -5; c = -15;
Δ = b2-4ac
Δ = -52-4·5·(-15)
Δ = 325
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{325}=\sqrt{25*13}=\sqrt{25}*\sqrt{13}=5\sqrt{13}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{13}}{2*5}=\frac{5-5\sqrt{13}}{10} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{13}}{2*5}=\frac{5+5\sqrt{13}}{10} $
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