5h-2(3/2h+4=10

Solution for 5h-2(3/2h+4=10 equation:

5h-2(3/2h+4=10

We move all terms to the left:

5h-2(3/2h+4-(10)=0


Domain of the equation: 2h+4-10!=0

We move all terms containing h to the left, all other terms to the right

2h!=6

h!=6/2

h!=3

h∈R


We multiply all the terms by the denominator


5h*2h+4-10-2(3=0

We add all the numbers together, and all the variables

5h*2h=0

Wy multiply elements

10h^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{0}{20}=0$