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5h-7=2(h+1)-3
We move all terms to the left:
5h-7-(2(h+1)-3)=0
We calculate terms in parentheses: -(2(h+1)-3), so:We get rid of parentheses
2(h+1)-3
We multiply parentheses
2h+2-3
We add all the numbers together, and all the variables
2h-1
Back to the equation:
-(2h-1)
5h-2h+1-7=0
We add all the numbers together, and all the variables
3h-6=0
We move all terms containing h to the left, all other terms to the right
3h=6
h=6/3
h=2
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