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5h=(-10)+3h
We move all terms to the left:
5h-((-10)+3h)=0
We calculate terms in parentheses: -((-10)+3h), so:We get rid of parentheses
(-10)+3h
determiningTheFunctionDomain 3h+(-10)
We add all the numbers together, and all the variables
3h-10
Back to the equation:
-(3h-10)
5h-3h+10=0
We add all the numbers together, and all the variables
2h+10=0
We move all terms containing h to the left, all other terms to the right
2h=-10
h=-10/2
h=-5
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