5h=2h(11-h)=-5

Solution for 5h=2h(11-h)=-5 equation:

5h=2h(11-h)=-5

We move all terms to the left:

5h-(2h(11-h))=0

We add all the numbers together, and all the variables

5h-(2h(-1h+11))=0


We calculate terms in parentheses: -(2h(-1h+11)), so:

2h(-1h+11)

We multiply parentheses

-2h^2+22h

Back to the equation:

-(-2h^2+22h)


We get rid of parentheses

2h^2-22h+5h=0

We add all the numbers together, and all the variables

2h^2-17h=0

a = 2; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·2·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*2}=\frac{0}{4}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*2}=\frac{34}{4}
=8+1/2
$