5i+2i-1=3(2i)

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Solution for 5i+2i-1=3(2i) equation: 



5i+2i-1=3(2i)

We move all terms to the left:

5i+2i-1-(3(2i))=0

determiningTheFunctionDomain
5i+2i-32i-1=0

We add all the numbers together, and all the variables

-25i-1=0

We move all terms containing i to the left, all other terms to the right

-25i=1

i=1/-25

i=-1/25

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