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5k-3=3(2k+1)-2k
We move all terms to the left:
5k-3-(3(2k+1)-2k)=0
We calculate terms in parentheses: -(3(2k+1)-2k), so:We get rid of parentheses
3(2k+1)-2k
We add all the numbers together, and all the variables
-2k+3(2k+1)
We multiply parentheses
-2k+6k+3
We add all the numbers together, and all the variables
4k+3
Back to the equation:
-(4k+3)
5k-4k-3-3=0
We add all the numbers together, and all the variables
k-6=0
We move all terms containing k to the left, all other terms to the right
k=6
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