5m(4m+8)=0

Solution for 5m(4m+8)=0 equation:

5m(4m+8)=0

We multiply parentheses

20m^2+40m=0

a = 20; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·20·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*20}=\frac{-80}{40}
=-2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*20}=\frac{0}{40}
=0
$