5m(m+3)=3

Solution for 5m(m+3)=3 equation:

5m(m+3)=3

We move all terms to the left:

5m(m+3)-(3)=0

We multiply parentheses

5m^2+15m-3=0

a = 5; b = 15; c = -3;
Δ = b2-4ac
Δ = 152-4·5·(-3)
Δ = 285
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{285}}{2*5}=\frac{-15-\sqrt{285}}{10}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{285}}{2*5}=\frac{-15+\sqrt{285}}{10}
$