5m(m-9)=0

Solution for 5m(m-9)=0 equation:

5m(m-9)=0

We multiply parentheses

5m^2-45m=0

a = 5; b = -45; c = 0;
Δ = b2-4ac
Δ = -452-4·5·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-45}{2*5}=\frac{0}{10}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+45}{2*5}=\frac{90}{10}
=9
$