5m+10=10(1/2m+1)

Solution for 5m+10=10(1/2m+1) equation:

5m+10=10(1/2m+1)

We move all terms to the left:

5m+10-(10(1/2m+1))=0


Domain of the equation: 2m+1))!=0

m∈R


We multiply all the terms by the denominator


5m*2m+10*2m+1))-(10(1+1))=0

We add all the numbers together, and all the variables

5m*2m+10*2m+1))-(102)=0

We add all the numbers together, and all the variables

5m*2m+10*2m=0

Wy multiply elements

10m^2+20m=0

a = 10; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·10·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*10}=\frac{-40}{20}
=-2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*10}=\frac{0}{20}
=0
$