5m-3(m+1)=2(m+1)-5

Solution for 5m-3(m+1)=2(m+1)-5 equation:

Simplifying
5m + -3(m + 1) = 2(m + 1) + -5

Reorder the terms:
5m + -3(1 + m) = 2(m + 1) + -5
5m + (1 * -3 + m * -3) = 2(m + 1) + -5
5m + (-3 + -3m) = 2(m + 1) + -5

Reorder the terms:
-3 + 5m + -3m = 2(m + 1) + -5

Combine like terms: 5m + -3m = 2m
-3 + 2m = 2(m + 1) + -5

Reorder the terms:
-3 + 2m = 2(1 + m) + -5
-3 + 2m = (1 * 2 + m * 2) + -5
-3 + 2m = (2 + 2m) + -5

Reorder the terms:
-3 + 2m = 2 + -5 + 2m

Combine like terms: 2 + -5 = -3
-3 + 2m = -3 + 2m

Add '3' to each side of the equation.
-3 + 3 + 2m = -3 + 3 + 2m

Combine like terms: -3 + 3 = 0
0 + 2m = -3 + 3 + 2m
2m = -3 + 3 + 2m

Combine like terms: -3 + 3 = 0
2m = 0 + 2m
2m = 2m

Add '-2m' to each side of the equation.
2m + -2m = 2m + -2m

Combine like terms: 2m + -2m = 0
0 = 2m + -2m

Combine like terms: 2m + -2m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.