5m-7/m=2/3

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Solution for 5m-7/m=2/3 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

5*m-(7/m) = 2/3 // - 2/3

5*m-(7/m)-(2/3) = 0

5*m-7*m^-1-2/3 = 0

5*m^1-7*m^-1-2/3*m^0 = 0

(5*m^2-2/3*m^1-7*m^0)/(m^1) = 0 // * m^2

m^1*(5*m^2-2/3*m^1-7*m^0) = 0

m^1

5*m^2+(-2/3)*m-7 = 0

5*m^2+(-2/3)*m-7 = 0

DELTA = (-2/3)^2-(-7*4*5)

DELTA = 1264/9

DELTA > 0

m = ((1264/9)^(1/2)-(-2/3))/(2*5) or m = (-(-2/3)-(1264/9)^(1/2))/(2*5)

m = ((1264/9)^(1/2)+2/3)/10 or m = (2/3-(1264/9)^(1/2))/10

m in { (2/3-(1264/9)^(1/2))/10, ((1264/9)^(1/2)+2/3)/10} 

m in { (2/3-(1264/9)^(1/2))/10, ((1264/9)^(1/2)+2/3)/10 }

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