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5m/3m=2m
We move all terms to the left:
5m/3m-(2m)=0
Domain of the equation: 3m!=0We add all the numbers together, and all the variables
m!=0/3
m!=0
m∈R
-2m+5m/3m=0
We multiply all the terms by the denominator
-2m*3m+5m=0
We add all the numbers together, and all the variables
5m-2m*3m=0
Wy multiply elements
-6m^2+5m=0
a = -6; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-6)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-6}=\frac{-10}{-12} =5/6 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-6}=\frac{0}{-12} =0 $
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