5m2+10m-80=75

Solution for 5m2+10m-80=75 equation:

5m^2+10m-80=75

We move all terms to the left:

5m^2+10m-80-(75)=0

We add all the numbers together, and all the variables

5m^2+10m-155=0

a = 5; b = 10; c = -155;
Δ = b2-4ac
Δ = 102-4·5·(-155)
Δ = 3200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3200}=\sqrt{1600*2}=\sqrt{1600}*\sqrt{2}=40\sqrt{2}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-40\sqrt{2}}{2*5}=\frac{-10-40\sqrt{2}}{10}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+40\sqrt{2}}{2*5}=\frac{-10+40\sqrt{2}}{10}
$