5m2+11m-6=0

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Solution for 5m2+11m-6=0 equation:



5m^2+11m-6=0
a = 5; b = 11; c = -6;
Δ = b2-4ac
Δ = 112-4·5·(-6)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{241}}{2*5}=\frac{-11-\sqrt{241}}{10} $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{241}}{2*5}=\frac{-11+\sqrt{241}}{10} $

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