5m2-22m+8=0

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Solution for 5m2-22m+8=0 equation:



5m^2-22m+8=0
a = 5; b = -22; c = +8;
Δ = b2-4ac
Δ = -222-4·5·8
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-18}{2*5}=\frac{4}{10} =2/5 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+18}{2*5}=\frac{40}{10} =4 $

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