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5m^2-54=0
a = 5; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·5·(-54)
Δ = 1080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1080}=\sqrt{36*30}=\sqrt{36}*\sqrt{30}=6\sqrt{30}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{30}}{2*5}=\frac{0-6\sqrt{30}}{10} =-\frac{6\sqrt{30}}{10} =-\frac{3\sqrt{30}}{5} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{30}}{2*5}=\frac{0+6\sqrt{30}}{10} =\frac{6\sqrt{30}}{10} =\frac{3\sqrt{30}}{5} $
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