5m2=-160+60m

Solution for 5m2=-160+60m equation:

5m^2=-160+60m

We move all terms to the left:

5m^2-(-160+60m)=0

We add all the numbers together, and all the variables

5m^2-(60m-160)=0

We get rid of parentheses

5m^2-60m+160=0

a = 5; b = -60; c = +160;
Δ = b2-4ac
Δ = -602-4·5·160
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-20}{2*5}=\frac{40}{10}
=4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+20}{2*5}=\frac{80}{10}
=8
$