5m=+1+1+3m+6(2m+4)

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Solution for 5m=+1+1+3m+6(2m+4) equation: 



5m=+1+1+3m+6(2m+4)

We move all terms to the left:

5m-(+1+1+3m+6(2m+4))=0



We calculate terms in parentheses: -(+1+1+3m+6(2m+4)), so:

+1+1+3m+6(2m+4)

determiningTheFunctionDomain
3m+6(2m+4)+1+1

We add all the numbers together, and all the variables

3m+6(2m+4)+2

We multiply parentheses

3m+12m+24+2

We add all the numbers together, and all the variables

15m+26

Back to the equation:

-(15m+26)



We get rid of parentheses

5m-15m-26=0

We add all the numbers together, and all the variables

-10m-26=0

We move all terms containing m to the left, all other terms to the right

-10m=26

m=26/-10

m=-2+3/5

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