5n(29-n)=0

Solution for 5n(29-n)=0 equation:

5n(29-n)=0

We add all the numbers together, and all the variables

5n(-1n+29)=0

We multiply parentheses

-5n^2+145n=0

a = -5; b = 145; c = 0;
Δ = b2-4ac
Δ = 1452-4·(-5)·0
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21025}=145$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(145)-145}{2*-5}=\frac{-290}{-10}
=+29
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(145)+145}{2*-5}=\frac{0}{-10}
=0
$