5n+19=4n+35

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Solution for 5n+19=4n+35 equation: 



5n+19=4n+35

We move all terms to the left:

5n+19-(4n+35)=0

We get rid of parentheses

5n-4n-35+19=0

We add all the numbers together, and all the variables

n-16=0

We move all terms containing n to the left, all other terms to the right

n=16

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