5n+19=4n+35

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Solution for 5n+19=4n+35 equation:



5n+19=4n+35
We move all terms to the left:
5n+19-(4n+35)=0
We get rid of parentheses
5n-4n-35+19=0
We add all the numbers together, and all the variables
n-16=0
We move all terms containing n to the left, all other terms to the right
n=16

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