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5n+3=2(n+2)-2n
We move all terms to the left:
5n+3-(2(n+2)-2n)=0
We calculate terms in parentheses: -(2(n+2)-2n), so:We add all the numbers together, and all the variables
2(n+2)-2n
We add all the numbers together, and all the variables
-2n+2(n+2)
We multiply parentheses
-2n+2n+4
We add all the numbers together, and all the variables
4
Back to the equation:
-(4)
5n-1=0
We move all terms containing n to the left, all other terms to the right
5n=1
n=1/5
n=1/5
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