5n+4(n-3)=7n-(2n+2)

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Solution for 5n+4(n-3)=7n-(2n+2) equation: 



5n+4(n-3)=7n-(2n+2)

We move all terms to the left:

5n+4(n-3)-(7n-(2n+2))=0

We multiply parentheses

5n+4n-(7n-(2n+2))-12=0



We calculate terms in parentheses: -(7n-(2n+2)), so:

7n-(2n+2)

We get rid of parentheses

7n-2n-2

We add all the numbers together, and all the variables

5n-2

Back to the equation:

-(5n-2)



We add all the numbers together, and all the variables

9n-(5n-2)-12=0

We get rid of parentheses

9n-5n+2-12=0

We add all the numbers together, and all the variables

4n-10=0

We move all terms containing n to the left, all other terms to the right

4n=10

n=10/4

n=2+1/2

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