5n+4+1-2n=-8(3n-7)-(n-5)

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Solution for 5n+4+1-2n=-8(3n-7)-(n-5) equation: 



5n+4+1-2n=-8(3n-7)-(n-5)

We move all terms to the left:

5n+4+1-2n-(-8(3n-7)-(n-5))=0

We add all the numbers together, and all the variables

3n-(-8(3n-7)-(n-5))+5=0



We calculate terms in parentheses: -(-8(3n-7)-(n-5)), so:

-8(3n-7)-(n-5)

We multiply parentheses

-24n-(n-5)+56

We get rid of parentheses

-24n-n+5+56

We add all the numbers together, and all the variables

-25n+61

Back to the equation:

-(-25n+61)



We get rid of parentheses

3n+25n-61+5=0

We add all the numbers together, and all the variables

28n-56=0

We move all terms containing n to the left, all other terms to the right

28n=56

n=56/28

n=2

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