5n+7+n=3n-2+2(2n-1)

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Solution for 5n+7+n=3n-2+2(2n-1) equation: 



5n+7+n=3n-2+2(2n-1)

We move all terms to the left:

5n+7+n-(3n-2+2(2n-1))=0

We add all the numbers together, and all the variables

6n-(3n-2+2(2n-1))+7=0



We calculate terms in parentheses: -(3n-2+2(2n-1)), so:

3n-2+2(2n-1)

determiningTheFunctionDomain
3n+2(2n-1)-2

We multiply parentheses

3n+4n-2-2

We add all the numbers together, and all the variables

7n-4

Back to the equation:

-(7n-4)



We get rid of parentheses

6n-7n+4+7=0

We add all the numbers together, and all the variables

-1n+11=0

We move all terms containing n to the left, all other terms to the right

-n=-11

n=-11/-1

n=+11

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