5n-(2n+3)=2n-4(n+2)

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Solution for 5n-(2n+3)=2n-4(n+2) equation: 



5n-(2n+3)=2n-4(n+2)

We move all terms to the left:

5n-(2n+3)-(2n-4(n+2))=0

We get rid of parentheses

5n-2n-(2n-4(n+2))-3=0



We calculate terms in parentheses: -(2n-4(n+2)), so:

2n-4(n+2)

We multiply parentheses

2n-4n-8

We add all the numbers together, and all the variables

-2n-8

Back to the equation:

-(-2n-8)



We add all the numbers together, and all the variables

3n-(-2n-8)-3=0

We get rid of parentheses

3n+2n+8-3=0

We add all the numbers together, and all the variables

5n+5=0

We move all terms containing n to the left, all other terms to the right

5n=-5

n=-5/5

n=-1

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