5n-(n+4)=10-2(n-8)

Solution for 5n-(n+4)=10-2(n-8) equation:

5n-(n+4)=10-2(n-8)

We move all terms to the left:

5n-(n+4)-(10-2(n-8))=0

We get rid of parentheses

5n-n-(10-2(n-8))-4=0


We calculate terms in parentheses: -(10-2(n-8)), so:

10-2(n-8)

determiningTheFunctionDomain
-2(n-8)+10

We multiply parentheses

-2n+16+10

We add all the numbers together, and all the variables

-2n+26

Back to the equation:

-(-2n+26)


We add all the numbers together, and all the variables

4n-(-2n+26)-4=0

We get rid of parentheses

4n+2n-26-4=0

We add all the numbers together, and all the variables

6n-30=0

We move all terms containing n to the left, all other terms to the right

6n=30

n=30/6

n=5