5n-2(n+3)=2n-(4n+2)

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Solution for 5n-2(n+3)=2n-(4n+2) equation: 



5n-2(n+3)=2n-(4n+2)

We move all terms to the left:

5n-2(n+3)-(2n-(4n+2))=0

We multiply parentheses

5n-2n-(2n-(4n+2))-6=0



We calculate terms in parentheses: -(2n-(4n+2)), so:

2n-(4n+2)

We get rid of parentheses

2n-4n-2

We add all the numbers together, and all the variables

-2n-2

Back to the equation:

-(-2n-2)



We add all the numbers together, and all the variables

3n-(-2n-2)-6=0

We get rid of parentheses

3n+2n+2-6=0

We add all the numbers together, and all the variables

5n-4=0

We move all terms containing n to the left, all other terms to the right

5n=4

n=4/5

n=4/5

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