5n/3=(3n-7)/2

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Solution for 5n/3=(3n-7)/2 equation: 



5n/3=(3n-7)/2

We move all terms to the left:

5n/3-((3n-7)/2)=0

We calculate fractions


10n^2/()+(-((3n-7)*3)/()=0



We calculate terms in parentheses: +(-((3n-7)*3)/(), so:

-((3n-7)*3)/(

We multiply all the terms by the denominator


-((3n-7)*3)



We calculate terms in parentheses: -((3n-7)*3), so:

(3n-7)*3

We multiply parentheses

9n-21

Back to the equation:

-(9n-21)



We get rid of parentheses

-9n+21

Back to the equation:

+(-9n+21)



We get rid of parentheses

10n^2/()-9n+21=0

We multiply all the terms by the denominator


10n^2-9n*()+21*()=0

We add all the numbers together, and all the variables

10n^2-9n*()=0

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