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5n^2+2n-88=0
a = 5; b = 2; c = -88;
Δ = b2-4ac
Δ = 22-4·5·(-88)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-42}{2*5}=\frac{-44}{10} =-4+2/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+42}{2*5}=\frac{40}{10} =4 $
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