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5n^2+6n-27=0
a = 5; b = 6; c = -27;
Δ = b2-4ac
Δ = 62-4·5·(-27)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-24}{2*5}=\frac{-30}{10} =-3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+24}{2*5}=\frac{18}{10} =1+4/5 $
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