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5n^2-26n-24=0
a = 5; b = -26; c = -24;
Δ = b2-4ac
Δ = -262-4·5·(-24)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-34}{2*5}=\frac{-8}{10} =-4/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+34}{2*5}=\frac{60}{10} =6 $
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