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5n^2-31n+6=0
a = 5; b = -31; c = +6;
Δ = b2-4ac
Δ = -312-4·5·6
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-29}{2*5}=\frac{2}{10} =1/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+29}{2*5}=\frac{60}{10} =6 $
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