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5n^2-3n=26
We move all terms to the left:
5n^2-3n-(26)=0
a = 5; b = -3; c = -26;
Δ = b2-4ac
Δ = -32-4·5·(-26)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-23}{2*5}=\frac{-20}{10} =-2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+23}{2*5}=\frac{26}{10} =2+3/5 $
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