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5n^2-9n-1136=0
a = 5; b = -9; c = -1136;
Δ = b2-4ac
Δ = -92-4·5·(-1136)
Δ = 22801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22801}=151$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-151}{2*5}=\frac{-142}{10} =-14+1/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+151}{2*5}=\frac{160}{10} =16 $
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