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5p(p-1)=-(-6-4p)
We move all terms to the left:
5p(p-1)-(-(-6-4p))=0
We add all the numbers together, and all the variables
5p(p-1)-(-(-4p-6))=0
We multiply parentheses
5p^2-5p-(-(-4p-6))=0
We calculate terms in parentheses: -(-(-4p-6)), so:We get rid of parentheses
-(-4p-6)
We get rid of parentheses
4p+6
Back to the equation:
-(4p+6)
5p^2-5p-4p-6=0
We add all the numbers together, and all the variables
5p^2-9p-6=0
a = 5; b = -9; c = -6;
Δ = b2-4ac
Δ = -92-4·5·(-6)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{201}}{2*5}=\frac{9-\sqrt{201}}{10} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{201}}{2*5}=\frac{9+\sqrt{201}}{10} $
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